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Linear Polynomials Class 9

1.Introduction to Linear Polynomials Class 9

In this article “Introduction to Linear Polynomials Class 9”,we will learn about terms,constant,coefficient,variable etc. in a polynomial.Also we will read key points of polynomials.

Also Read This Article:- Class 9 Maths Polynomials:16 Important Descriptive Type Questions

2.Important key points of Polynomials

Basic Components of Algebraic Expressions:
(1.)Variables:Letter-numbers (e.g., x,y,z) used to represent unknown quantities.
(2.)Terms:Individual parts of an expression separated by addition or subtraction (e.g., in 4x+5y+3, the terms are 4x,5y and 3).
(3.)Coefficients:The numerical values multiplied by variables (e.g., in 4x,4 is the coefficient of x).
(4.)Constant:A term with a fixed numerical value containing no variables (e.g., 3).
Types of Polynomials by Number of Variables:
(5.)Multivariate Expressions:Involve two or more variables (e.g.,4x+5y+3 or 200l+160w+50lw).
(6.)Univariate (One-Variable) Polynomials:Algebraic expressions involving powers of a single variable (e.g., x^2 + 5x + 1).
(7.)Degree of a Polynomial:Defined as the highest power of the variable present in the algebraic expression.
(8.)Constant Polynomial (Degree 0):Highest power of variable is 0 (e.g.,8, which can be written as 8x^0).
(9.)Linear Polynomial (Degree 1):Highest power of variable is 1 (e.g., 3z+7).
(10.)Quadratic Polynomial (Degree 2):Highest power of variable is 2 (e.g., x^2 + 5x + 1 ).
(11.)Cubic Polynomial (Degree 3):Highest power of variable is 3 (e.g., y^3 + y^2 + 2y - 1).

Also Read This Article:- Polynomial

3.Linear Polynomials Class 9 Solved Problems

Illustrations 1. Find the degrees of the following polynomials:
Illustration: 1 (i) 2x^2 - 5x + 3
Solution: 2x^2 - 5x + 3
In above polynomial, highest power of variable of x is 2.
Hence degree of polynomial = 2.
Illustration: 1 (ii) y^3 + 2y - 1
Solution: y^3 + 2y - 1
In this polynomial highest power of variable y is 3.
Hence degree of polynomial is 3.
Illustration: 1 (iii) -9
Solution: -9
It is constant polynomial, and power of constant polynomial is zero.
Illustration: 1 (iv) 4z - 3
Solution: 4z - 3
This is linear polynomial and linear polynomial has one degree of variable.
Hence its degree is one.

Illustration: 2. Write polynomials of degrees 1, 2 and 3,
Solution: Polynomial degree of 1 = 2x+3, \frac{x}{2}+1, \text{etc.}
Polynomial of degree 2:
= x^2+3, \frac{x^2}{5}-5, 4x^2+2x-3
Polynomial of degree 3:
= x^3-3x^2+3x+1, x^3-1, \text{etc.}
Illustration: 3. What are the coefficient of x^2 and x^3 in the polynomial
x^4 - 3x^3 + 6x^2 - 2x + 7?
Solution: x^4 - 3x^3 + 6x^2 - 2x + 7
Coefficient of x^2 = 6
Coefficient of x^3 = -3
Illustration: 4. What is the coefficient of z in the polynomial
4z^3 + 5z^2 - 11?
Solution: 4z^3 + 5z^2 - 11
Coefficient of z = 0
Illustration: 5. What is the constant term of the polynomial
9x^3 + 5x^2 - 8x - 10?
Solution: 9x^3 + 5x^2 - 8x - 10
Constant term of polynomial = -10

Also Read This Article :- Class 9 Maths Number System:13 Important Questions (MCQ and Descriptive)

4.Practice Problems of Linear Polynomials Class 9 for Students

Which is polynomial of following expressions.Give reasons.
(1.) \sqrt{x} + 5
(2.) x + \frac{1}{x}
(3.) \frac{x^2}{3} - \frac{1}{2}
(4.) x^3 - 3x + 5x^2 + 1
By solving the above questions,one can understand the Linear Polynomials Class 9 well because the concept is well understood when you solve the questions practically.

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5.Frequentaly Asked Questions Related to Linear Polynomials Class 9

Q:1.what is a linear polynomial?

Ans.A polynomial of degree 1,such polynomial are called linear polynomials.

Q:2.What is meant by term?

Ans.If the algebraic expression is given by 4x+5y+3 then 4x,5y and 3 are terms.

Q:3.Explain the coefficient

Ans.In the above enamples 4 and 5 are the coefficients of x and y respectively.
By answering the above questions,you can know about the primary terms of Linear Polynomials Class 9.

6.छात्र-छात्राओं से आज का प्रश्न (Today’s Question to Students):

🎯 विनर्स कॉर्नर:क्या आप इस सवाल का सही जवाब दे सकते हैं?अपने नाम के साथ नीचे कमेंट करें!सही जवाब देने वाले Top Students के नाम हमारी आगे post/is article ke update में Photo ya Special Mention के साथ publish की जाएगी।अपना जवाब अभी दर्ज करें!👇
Q. (100)^{\frac{1}{2}} \times (0.001)^{\frac{1}{3}} - (0.0016)^{\frac{1}{4}} + \left(\frac{5}{4}\right)^{-1}
को सरल करके मान बताइए
(Simplify (100)^{\frac{1}{2}} \times (0.001)^{\frac{1}{3}} - (0.0016)^{\frac{1}{4}} + \left(\frac{5}{4}\right)^{-1} and give the value.)
*पिछली प्रश्नोत्तरी का उत्तर* \frac{4}{9}
चूँकि 0.111\dots = \frac{1}{9} अतः 0.444 \cdots = 0.111 \cdots \times 4 = 0.444\dots
माना x = 0.444 \cdots \\ 10x =4.444 \cdots \\ \Rightarrow 9x = 4 \Rightarrow x = \frac{4}{9}
*Previous Quiz Solution* \frac{4}{9}
Since 0.111\dots = \frac{1}{9} therefore 0.444 \cdots = 0.111 \cdots \times 4 = 0.444\dots
Let x = 0.444 \cdots \\ 10x =4.444 \cdots \\ \Rightarrow 9x = 4 \Rightarrow x = \frac{4}{9}
*”This article has been prepared by **Satyam Coaching Centre** on the **Satyam Mathematics** blog.”*

 

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